How do you solve #3y + 2 - 5(y+1) = -3#?

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Answer 1 · 2016-02-06T03:30:34

#y=0#

Given _

#3y+2-5(y+1)=-3#
#3y+2-5y-5=-3#
#-2y=-3-2+5#
#-2y=0#
#y=0/(-2)#
#y=0#

Answer 2 · 2016-02-06T06:45:07

#3y+2-5(y+1)=-3#

Use distributive formula #a(b+c)=ab+ac#

#rarr3y+2-5y-5=-3#

#rarr-2y+2-5=-3#

#rarr-2y-3=-3#

#rarr-2y=-3+3#

#rarr-2y=0#

#y=0/-2=0#