Question

The first three terms of an arithmetic series are x-1, 5x-3, 4x+5, how do you find the sixth term?

Answer 1

The sixth term is `31`

Explanation:

It should be

`5x-3-(x-1)=4x+5-(5x-3)=>4x-2=8-x=>5x=10=>x=2`

Hence the first three terms are `2-1=1`,`5*2-3=7`,`4*2+5=13`

So it is an arithmetic series with first term `a_1=1` and ratio `r=6`

hence

`a_6=a_1+(6-1)*6=1+30=31`