How do solve the following linear system?: # -8x + y = 2 , 8x + 3y= -9 #?

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Answer 1 · 2016-02-07T09:33:42

Solve by elimination and substitution:

#-8x+y=2,8x+3y=-9#

Eliminate #8x# from the second equation by #-8x# in the first equation:

Add both the equations:

#rarr(-8x+y=2)+(8x+3y=-9)#

#rarr4y=-7#

#rarry=-7/4#

Substitute the value of #y# to the first equation:

#rarr-8x+(-7/4)=2#

#rarr-8x-7/4=2#

#rarr(-32x-7)/4=2#

#rarr-32x-7=4*2#

#rarr-32x-7=8#

#rarr-32x=8+7#

#rarr-32x=15#

#rarrx=-15/32#:)