How do you divide #20 / (3+i)#? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer Tony B Feb 7, 2016 #7.5-2.5i ->14/2-5/2i# Explanation: Given: #" "20/(3+i)# Multiply by 1 but in the form of: #(3-i)/(3-i)# #20/(3+i)xx(3-i)/(3-i)# #(20(3-i))/(9-i^2)# #(20(3-i))/8# #7.5-2.5i ->14/2-5/2i# Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient #(-5+i)/(-7+i)#? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of #12/(5i)#? How do I rationalize the denominator of a complex quotient? How do I divide #6(cos^circ 60+i\ sin60^circ)# by #3(cos^circ 90+i\ sin90^circ)#? How do you write #(-2i) / (4-2i)# in the "a+bi" form? See all questions in Division of Complex Numbers Impact of this question 1156 views around the world You can reuse this answer Creative Commons License