A balanced lever has two weights on it, the first with mass $9 k g$ $9 kg$ and the second with mass $72 k g$ $72 kg$ . If the first weight is $16 m$ $16 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-02-07T20:12:12

$y = 2 m$ $y=2m$

$F_{1} \cdot x = F_{2} \cdot y$ $F_1*x=F_2*y$
$cancel(9)*16=cancel(72)*y$
$cancel(16)=cancel(8)*y$
$y=2m$

A balanced lever has two weights on it, the first with mass 9 kg 9kg9 kg and the second with mass 72 kg72kg72 kg. If the first weight is 16 m16m 16 m from the fulcrum, how far is the second weight from the fulcrum?