How do you differentiate #f(x)=xlnx # using the product rule?
1 Answer
Feb 8, 2016
Explanation:
For
#f'(x) = g'(x) * h(x) + g(x) * h'(x)#
In your case, let
Let's compute the derivatives of
#g(x) = x " " => " " g'(x) = 1#
#h(x) = ln x " " => " " h'(x) = 1/x#
Thus, you can compute the derivative as follows:
#f'(x) = g'(x) * h(x) + g(x) * h'(x)#
# = 1 * ln x + x * 1/x #
# = ln x + 1 #