Question

A charge of `2 C` is at `(5, 2)` and a charge of `-3 C` is at `( 4, -9 )`. If both coordinates are in meters, what is the force between the charges?

Answer 1

`F_(AB)~=0,4426*10^9 N`

Explanation:

`"distance between the point A and B is given by:"`
`r_(AB)^2=(4-5)^2+(-9-2)^2`
`r_(AB)^2=1+121`
`r_(AB)^2=122`
`"force between two charge is given by Coulomb's law"`
`F_(AB)=k* (- q_A * q_B)/r^2`
`F_(AB)=(9*10^9*2*(-3))/r^2`
`F_(AB)=(-54*10^9)/122`
`F_(AB)~=0,4426*10^9 N`