Question

A charge of `-2 C` is at `(-7, 1 )` and a charge of `-3 C` is at `(3, 5 )`. If both coordinates are in meters, what is the force between the charges?

Answer 1

`F_(q_1q_2)~=0,46551*10^9 " N"`

Explanation:

`" first; calculate distance between (-7,1) and (3,5)"`
`r^2=(3+7)^2+(5-1)^2)`
`r^2=100+16`
`r^²=116`
`"Force between two charge is given formula by:"`
`F_(q_1q_2)=(k*q_1*q_2)/r^2`
`F_(q_1q_2)=(9*10^9*(-2)*(-3))/116`
`F_(q_1q_2)=(54*10^9)/116`
`F_(q_1q_2)~=0,46551*10^9 " N"`