Question

Question #716c5

Answer 1

The frictional force experienced by block is `0.98N`

Explanation:

Here's how your question looks like diagrammatically.

Given force `F` of `5N` is applied to the box to keep it on the surface.
The box is of `0.1kg` and its subsequent weight is `0.98N`
Since the normal force is the equal to the force exerted on the surface by the box, then `N=F=5N`
That means the maximum static frictional force the surface can exert is `\mu_sN=0.5*5=2.5N`

But this isn't the end of it yet. We have to find out what exactly the frictional force is. Because even if the maximum frictional force is `2.5N`, this isn't the force always experienced, it actually also depends on the force that causes the box to move, which here would be the force of gravity `Mg`
Seeing that `Mg=0.98N`, this means that the force of friction experienced by the object is actually `0.98N`
This is because the only maximum force of friction depends on normal force, but the value the object will experience will be the force that tries to move it.