Question

What are the mean and standard deviation of a binomial probability distribution with `n=87` and `p=5/37`?

Answer 1

Mean `=11 28/37`
SD `=3.22`

Explanation:

Given -

`n=87`
`p=5/37`

Mean `bar x=np=87xx5/37=11 28/37`
SD `sigma=sqrt(npq)`

`q=1-p=1-5/37=32/37`
SD `sigma=sqrt(87xx5/37xx32/37)=sqrt(10.17)=3.22`