How do you find the number of molecules or ions of .25 mol $K^{+}$ $K^+$ ?

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How do you find the number of molecules or ions of .25 mol $K^{+}$ $K^+$ ?

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Answer 1 · 2016-02-13T09:19:02

it is 0.25x avogadro's no, since one mole contains avogadro's no. of particles

Answer 2 · 2016-02-13T10:14:53

$1$ $1$ $m o l$ $mol$ of potassium atoms has Avogadro's number, $N_{A}$ $N_A$ , i.e. $6.022 \times 10^{23}$ $6.022xx10^23$ individual potassium atoms.

Explanation:

You have $0.25$ $0.25$ moles of potassium ions: i.e. $\frac{1}{4} \times N_{A}$ $1/4xxN_A$ $=$ $=$ $? ?$ $??$ $≅$ $~=$ $1.5 \times 10^{23}$ $1.5xx10^23$ . Capisce?

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How do you find the number of molecules or ions of .25 mol $K^{+}$ $K^+$ ?

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