Question #973fb

1 Answer
anor277
Feb 13, 2016

#8.98# #xx# #N_A#, where #N_A# is Avogadro's number, #6.022xx10^23# #mol^-1#.

Explanation:

So the answer is # ~= # #54xx10^23# individual formula units of #AlCr_2O_7Cl#. In this quantity, how many individual ATOMS of aluminum, of chromium, of oxygen?

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