How do you solve the following system: #x-2y=3, -6x + y = -8 #?

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Answer 1 · 2016-02-13T17:45:15

The solution for the system of equations is:

#x=13/11#
#y=-10/11#

#x-color(blue)(2y)=3#....................equation #(1)#

#-6x+y=-8#, multiplying by #2#
#-12x+color(blue)(2y)=-16#.......equation #(2)#

Solving by elimination

Adding equations #1# and #2#

#x-cancelcolor(blue)(2y)=3#

#-12x+cancelcolor(blue)(2y)=-16#

#-11x =-13#

#x =(-13)/(-11)#

#x =13/11#

Finding #y# from equation #1#
#x - 2y=3#

#2y=x-3#

#2y=13/11-3#

#2y=13/11-33/11#

#2y=-20/11#

#y=-cancel20/(11xxcancel2)#

#y=-10/11#