Question

How do you use Heron's formula to find the area of a triangle with sides of lengths `3`, `5`, and `4`?

Answer 1

Heron's formula states that:
`A=sqrts(s-a)(s-b)(s-c)`

where s is equal to:
`s=(a+b+c)/2`

If a=3. b=5, and c=4, then plugging in the numbers. we get:
`s=(3+5+4)/2=6`

so:
`A=sqrt6(6-3)(6-5)(6-4)=sqrt36` which can be further simplified to just 6, due to the fact that `sqrt36=6`