Question

A charge of `5 C` is at `(9 , 3 )` and a charge of `-1 C` is at `(-2 , 4 )`. If both coordinates are in meters, what is the force between the charges?

Answer 1

`F~=-0,369*10^9N`

Explanation:

`"distance between (9,3) and (-2,4):"`
`r²=(-2-9)^2+(4-3)^2`
`r^2=(-11)^2+1^2`
`r^2=121+1`
`r^2=122`
`"Force between two charges is defined as Coulomb's law"`
`F=(k*q_1*q_2)/r^2`
`F=(k*5*(-1))/122`
`F=(-5*k)/122`
`F=(-5*9*10^9)/122`
`F~=-0,369*10^9N`