What is the derivative of #tan 2x^3#?
1 Answer
Feb 14, 2016
#6x^2sec^2(2x^3) #
Explanation:
differentiate using the
#color(blue)(" chain rule") #
# d/dx(f(g(x)) = f'g(x).g'(x) #
#d/dx[tan(2x^3)] = sec^2(2x^3) d/dx(2x^3) =sec^2(2x^3).6x^2#