Question

An object with a mass of `32 g` is dropped into `480 mL` of water at `0^@C`. If the object cools by `120 ^@C` and the water warms by `9 ^@C`, what is the specific heat of the material that the object is made of?

Answer 1

`c_o=1,125 " may be ammonia liquid"`

Explanation:

`Q_o=m_o*c_o*Delta t_o" Heat given by object a mass of 32 g"`
`c_o": specific heat of object"`
`Q_o=32*c_o*120`
`Q_o=3840*c_o`
`Q_w=m_w*c_w*Delta t_w" Heat gained by water"`
`V_=480 m ; m_=480 g ; c_w=1`
`Q_w=480*1*9`
`Q_w=4320 Cal`
`Q_o=Q_w " conversation of energy"`
`3840*c_o=4320`
`c_o=4320/3840`
`c_o=1,125 " may be ammonia liquid"`