A charge of $18 C$ $18 C$ passes through a circuit every $24 s$ $24 s$ . If the circuit can generate $4 W$ $4 W$ of power, what is the circuit's resistance?

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A charge of $18 C$ $18 C$ passes through a circuit every $24 s$ $24 s$ . If the circuit can generate $4 W$ $4 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-02-19T05:19:04

may be solved as follows

Explanation:

calculation of current strength I = $\frac{Q}{t} = \frac{18}{24} A$ $Q/t=18/24A$
Now Power (P) = $I^{2} \cdot R$ $I^2*R$
here P =4W
hence $R = \frac{p}{I^{2}} = 4 \cdot \frac{24^{2}}{18^{2}}$ $R=p/I^2=4*24^2/18^2$ ohm=7.11 ohm

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A charge of $18 C$ $18 C$ passes through a circuit every $24 s$ $24 s$ . If the circuit can generate $4 W$ $4 W$ of power, what is the circuit's resistance?

1 Answer

Explanation:

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A charge of 18 C18C18 C passes through a circuit every 24 s24s24 s. If the circuit can generate 4 W4W4 W of power, what is the circuit's resistance?

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A charge of $18 C$ $18 C$ passes through a circuit every $24 s$ $24 s$ . If the circuit can generate $4 W$ $4 W$ of power, what is the circuit's resistance?