Question

A charge of `18 C` passes through a circuit every `24 s`. If the circuit can generate `4 W` of power, what is the circuit's resistance?

Answer 1

may be solved as follows

Explanation:

calculation of current strength I = `Q/t=18/24A`
Now Power (P) =`I^2*R`
here P =4W
hence `R=p/I^2=4*24^2/18^2` ohm=7.11 ohm