A charge of $18 C$ passes through a circuit every $24 s$ . If the circuit can generate $4 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-02-19T05:19:04

may be solved as follows

calculation of current strength I = $Q/t=18/24A$
Now Power (P) = $I^2*R$
here P =4W
hence $R=p/I^2=4*24^2/18^2$ ohm=7.11 ohm

A charge of 18 C18 C passes through a circuit every 24 s24 s. If the circuit can generate 4 W4 W of power, what is the circuit's resistance?