Question

What is the standard form of `y= (-x-5)(8x-2)`?

Answer 1

`-8x^2 - 38x + 10`

Explanation:

Standard form for an expression is listing the terms , beginning with the term with the highest exponent of the variable followed by decreasing exponents until the last term , usually a constant.

begin by distributing the brackets.
Each term in the 2nd bracket must be multiplied by each term in the 1st.This can be done as follows.

thus : -x(8x - 2) - 5 (8x - 2 )

hence `-8x^2 + 2x - 40x + 10 = -8x^2 - 38x + 10`

This expression is in standard form.