What is the sum of the arithmetic sequence 8, 14, 20 …, if there are 24 terms?
1 Answer
Feb 19, 2016
1848
Explanation:
The sum to n terms of an arithmetic sequence is found by using
#S_n = n/2[2a + (n-1)d ]# where a , is the first term and d , the common difference
here a = 8 and d = 14 - 8 = 20 - 14 =.......= 6
hence
# S_24 = 24/2[ (2xx8) +(23xx6) ]# = 12[ 16 + 138 ] = 12( 154) = 1848
