A ball with a mass of 12kg moving at 4 m/s hits a still ball with a mass of 2 kg. If the first ball stops moving, how fast is the second ball moving?

1 Answer
Feb 24, 2016

v_2=24ms^-1

Explanation:

This is a simple case of conservation of linear momentum. This means that m_1v_1=m_2v_2.
Reason why is because they said that the first ball stops, so the velocity of the first ball after collision is 0 and that reduces our equation so.

We have, m_1=12kg, m_2=2kg, v_1=4ms^-1, so we have to find v_2.

So, 12*cancel{4}^2=cancel{2}^1*v_2

I'm sure it gets simple from here.