Question

Question #2128f

Answer 1

`x=2`

Explanation:

`x^2 + y^2 = 8`
`x-y =4`

`:.y = x-4`

substituting this back into the first equation gives
`x^2 + (x-4)^2 = 8`

`x^2 +x^2 - 8x +16 = 8`
`2x^2 - 8x +8 =0`
`x^2 -4x +4 = 0`
`(x-2)^2 = 0`

`:.x=2`