Question

How many moles of `Pb` is in `9.34 * 10^15` atoms of `Pb`?

Answer 1

Approx. `10^-8` `"moles"`.

Explanation:

`N_A` `=` `6.022xx10^23`

So, `(9.34xx10^15*"lead atoms")/(6.022xx10^23" lead atoms mole"^-1)` `=` `??"mole"`