Question

How do you write the equation in point slope form given (-1, -2), perpendicular to y = -3x + 3?

Answer 1

`y--2=1/3(x--1)" " "`point slope form

Explanation:

We have a given point `(x_1, y_1)=(-1, -2)` and the line is suppose to contain this point with a slope `m=-1/(-3)=1/3`

point slope form: `(y-y_1)=m(x-x_1)`

`y--2=1/3(x--1)`

the graph of the lines look like as follows

graph{(y--2-1/3(x--1))(y+3x-3)=0[-10,10,-5,5]}

God bless...I hope the explanation is useful...