How do you use substitution to solve the system of equations #x+3y=10# and #x=2y-5#?

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Answer 1 · 2016-02-26T15:06:38

The solution is:
#x=1, y=3#

#x+3y=10#......equation #(1)#
#color(blue)(x = 2y-5#.......equation #(2)#

Solving by substitution :

Substituting #x# from equation #2# in equation #1#:

#x+3y=10#

#color(blue)( 2y-5)+3y=10#

#5y- 5=10#

#5y=10 +5#

#y=15/5#

#y=3#

Substituting #y# in equation #1# to find #x#
#x+3y=10#

#x+3 xx 3=10#

#x=10- 9#

#color(blue)(x=1#