Question

What is the derivative of `f(x) = cot^2(x)cos(x)`?

Answer 1

Hence `cotx=cosx/sinx` we have that

#f(x) = cot^2(x)cos(x)=>f(x)=(cosx/sinx)^2*cos(x)=> f(x)=cos^3x/sinx#

Using the quotient rule for differentiation we get

`(df(x))/dx=(cos2x-2)*cot^2x`