How do you use polynomial division to divide #x^3 + x^2 - 10x - 6# by x-3? Precalculus Real Zeros of Polynomials Synthetic Division 1 Answer Konstantinos Michailidis Feb 27, 2016 First we notice that #x^3 + x^2 - 10x - 6=(x-3)(x^2+4x+2)# hence #(x^3+x^2-10-6)/(x-3)=x^2+4x+2# Answer link Related questions What is synthetic division? What are common mistakes students make with synthetic division? How do I find the quotient and remainder using synthetic division? How do you write the remainder in synthetic division? How do I find the quotient #(x^3+5x^2+x-15)/(x+3)# by using synthetic division? How do I find the roots of a polynomial function by using synthetic division? How can synthetic division be used to factor a polynomial? How do I use synthetic division to find #p(-3)# for #p(x)=x^4-2x^3-4x+4#? Use synthetic division to find #p(4)# for #p(x)=x^4-2x^3-4x+4#? How do you use synthetic division to evaluate #f(3)# given that #f(x)=x^3+2x^2-7x+8#? See all questions in Synthetic Division Impact of this question 1297 views around the world You can reuse this answer Creative Commons License