Question

What is the constant term of the expansion of `((x-(2/x^2))^9`?

Answer 1

Using the binomial theorem you get

`(x-2/x^2)^9=-512/x^18+2304/x^15-4608/x^12+x^9+5376/x^9-18 x^6-4032/x^6+144 x^3+2016/x^3-672`

Hence the constant term is `-672`