Question

How many molecules of `NH_3` are produced from `4.82*10^-4` `g` of `H_2`?

Answer 1

`9.58xx10^(19)"molecules"NH_3`

Explanation:

The reaction of making `NH_3` from `H_2` is the following:

`3H_2(g)+N_2(g)->2NH_3(g)`

Therefore, using dimensional analysis, we can use the molar ratio from the balanced equation to find the number of molecules of `NH_3` produced by:

`?"molecules"NH_3=4.82xx10^(-4)cancel(gH_2)xx(1cancel(molH_2))/(2.02cancel(gH_2))xx(2cancel(molNH_3))/(3cancel(molH_2))xx(6.022xx10^(23)"molecules"NH_3)/(1cancel(molNH_3))=9.58xx10^(19)"molecules"NH_3`