How do you find the inverse of #((7, -4),(-5, 3))#?
1 Answer
Feb 28, 2016
Explanation:
For a 2X2 matrix A , the inverse is found as follows:
For a matrix A =
#((a,b),(c,d))# Then the inverse
#A^-1 = 1/(ad-bc)((d,-b),(-c,a))# (ad - bc) is the determinant of the matrix , and if equal to zero, then the matrix has no inverse and is said to be singular.
here a = 7 b = -4 , c = -5 and d = 3
ad - bc =
#(7xx3) - (-4xx-5) = 21 -20 = 1 # hence an inverse matrix exists
#rArr A^-1 =( (3,4),(5,7))#