Question

How do you solve `6=1-2n+5`?

Answer 1

`n=0`

Explanation:

Given equation is `6=1-2n+5`

This is a case of simple algebra of "finding x" type questions.

So, we here, what we'll first do is subtract `1` from both sides, so
`6-1=1-2n+5-1\implies5=-2n+5`

Now, we'll again subtract `5` from both sides, so `5-5=-2n+5-5\implies 0=-2n`

Well, now what we'll have to do is divide both sides by the value `2`. So, `0/2=-cancel{2}^1/cancel{2}^1*n`. Since `0/2=0`, `-n=0`
Multiply by `-1` on both sides, `-1*-n=-1*0`

since `-1*0=0`, we are left with nothing but the answer.