What is the speed of an object that travels from ( 8,-4,2) to ( 7,-3,6 ) over 3 s?

1 Answer
Feb 29, 2016

v=sqrt 2 m/s

Explanation:

"Distance the point (8,-4,2) and (7,-3,6) may be calculated using:"
Delta x=sqrt((7-8)^2+(-3+4)^2+(6-2)^2)=sqrt(1+1+16)=sqrt 18 m
"The speed of an object is given by :"v=(Delta x)/t
v=sqrt 18/3
v=sqrt (9*2)/3
v=3*sqrt 2/3
v=sqrt 2 m/s