How do you solve #-1/5b - 2/5 = -2#?

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Answer 1 · 2016-03-02T11:05:19

#b=8#

#-1/5 b-2/5=-2#

Divide each term by #-1#

#rarr1/5 b+2/5=2#

#rarr1/5 b=2-2/5#

#rarr1/5 b=8/5#

#rarrb/5=8/5#

#:.b=8#