Question

For what values of x, if any, does `f(x) = 1/((x-5)(x+6))` have vertical asymptotes?

Answer 1

x = 5 , x = -6

Explanation:

Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation let the denominator equal zero.

solve: (x - 5 )(x + 6 ) = 0 → x = 5 x = -6 are the equations.

Here is the graph of the function.
graph{1/((x-5)(x+6)) [-10, 10, -5, 5]}