How do you find the derivative of # arctan (cos x)#?
1 Answer
Mar 3, 2016
Explanation:
using the
#color(blue)" chain rule "#
#d/dx[f(g(x))] = f'(g(x)) . g'(x)# and the standard derivative
#d/dx(tan^-1 x) = 1/(1+x^2)#
#d/dx[tan^-1(cosx)] = 1/(1+ cos^2 x) . d/dx(cosx)#
#= (-sinx)/(1 + cos^2 x) #
