An object with a mass of 6 kg6kg is moving at 7 m/s7ms over a surface with a kinetic friction coefficient of 2 2. How much power will it take to accelerate the object at #8 m/s^2?

1 Answer
Mar 4, 2016

P = W/ t = F *s/t = Fv = 168 * 7 = 1176WP=Wt=Fst=Fv=1687=1176W

Explanation:

P = W/ t = F *s/t = FvP=Wt=Fst=Fv

f = mu mg = 2 * 6 * gf=μmg=26g
a_f = mu g = 2* 10 =20af=μg=210=20

F_(Net) = m_(Net) a_(Net)FNet=mNetaNet

a _( Net) = a_f + a = 8 + 20 = 28 m/s^2 aNet=af+a=8+20=28ms2

F_(Net) = m_(Net) a_(Net) = 6 * 28 = 168 NFNet=mNetaNet=628=168N

P = W/ t = F *s/t = Fv = 168 * 7 = 1176WP=Wt=Fst=Fv=1687=1176W