How do you write the equation in slope intercept form perpendicular to y = -4x -2 and passes through the point (-16, -11)?

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Answer 1 · 2016-03-05T05:34:34

#y' = 1/4x' - 7#

#y = -4x - 2#

#=> m = -4#

#m' = -1/m#

#=> m' = -1/-4 = 1/4#

#y' = m'x' + b'#

#=> y' = 1/4x' + b'#

#=> -11 = 1/4(-16) + b'#

#=> -11 = -4 + b'#

#=> b' = -7#

#y' = 1/4x' - 7#