Question

What is `(y^-2)^4/((2x^3y^-2)^-3`?

Answer 1

It is `8x^9*y^-14`

Explanation:

It is

`(y^-2)^4/((2x^3y^-2)^-3)=(y^-2)^4*[2x^3y^-2]^3=y^-8*2^3*x^9*y^-6=8x^9*y^-14`