Question

How do you expand `log x (x^2+1)^(-.5)`?

Answer 1

`logx-0.5log(x^2+1)`

Explanation:

`logx+log(x^2+1)^-0.5`-> use property `log_bxy=log_bx+log_by`
`logx-0.5log(x^2+1)`->use property `log_bx^n =n*log_bx`