Question

If I start with 5 grams of `C_3H_8`, what is the theoretical yield of water in the equation `C_3H_8 + 5O_2 -> 3CO_2 + 4H_2O`?

Answer 1

`~~8.18gm`

Explanation:

the molar mass of`C_3H_8=3xx12+8xx1=44gmmol^=1`
molar mass of water=`18gmmol^-1`

As per the equation 44 gm`C_3H_8` gives `4xx18=72gm` water
1gm `C_3H_8` gives `4xx18=72/44gm` water
5gm `C_3H_8` gives `4xx18=72/44xx5~~8.18gm` water