How do you solve #6-7a + 1=7-3a#?

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Answer 1 · 2016-03-12T08:49:22

#a=0#

#6-7a+1=7-3a#

Add #3a# both sides

#rarr6-7a+1+3a=7-3a+3a#

#rarr6-4a+1=7#

#rarr7-4a=7#

#rarr-4a=7-7#

#rarr-4a=0#

#rArra=0/-4=0#

Check

#6-7(0)+1=7-3(0)#

#6+1=7#

#7=7# =)