What is the perimeter of a triangle with corners at #(6 ,5 )#, #(9 ,1 )#, and #(3 ,8 )#?

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Answer 1 · 2016-03-13T09:17:57

Perimeter P#=5+3sqrt2+sqrt85=18.4622" "#units

Compute the lengths of sides:

Side containing (6,5) and (9,1)

#d_1=sqrt((6-9)^2+(5-1)^2)=sqrt(9+16)=sqrt(25)=5#

Side containing (6,5) and (3,8)

#d_2=sqrt((6-3)^2+(5-8)^2)=sqrt(9+9)=sqrt(18)=3sqrt2#

Side containing (9,1) and (3,8)

#d_3=sqrt((9-3)^2+(1-8)^2)=sqrt(36+49)=sqrt(85)=sqrt85#

Perimeter P#=5+3sqrt2+sqrt85=18.4622" "#units

God bless....I hope the explanation is useful.