A balanced lever has two weights on it, one with mass $8 kg$ and one with mass $20 kg$ . If the first weight is $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-03-13T19:28:12

$x=1,6 m$

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$F_1*AE=F_2*BE$
$8*cancel(9,81)*cancel(4)=cancel(20)*cancel(9,81)*x$
$8=5*x$
$x=8/5$
$x=1,6 m$

A balanced lever has two weights on it, one with mass 8 kg8 kg and one with mass 20 kg20 kg. If the first weight is 4 m 4 m from the fulcrum, how far is the second weight from the fulcrum?