Question

A charge of `1 C` is at `(3,-2)` and a charge of `-3 C` is at `( 7,-1)`. If both coordinates are in meters, what is the force between the charges?

Answer 1

`F=-1,59*10^9" "N`

Explanation:

`F="force between two charges"`
`q_1,q_2:"charges"`
`d:"distance between two charges"`
`"The force between two charges is determined by :"`
`F=k(q_1*q_2)/d^2`
`"let's calculate distance between two charges"`
`P_1=(3,-2)`
`P_2=(7,-1)`
`Delta x=P_"2x"-P_"1x"=7-3=4`
`Delta y=P_"2y"-P_"1y"=-1+2=1`
`d=sqrt(Delta x^2+Delta y^2)" "d=sqrt(4^2+1^2)" "d=sqrt17`
`F=k(1*(-3))/(sqrt17)^2`
`F=(-3k)/17" "k=9*10^9 N*m^2*C^-2`
`F=(-3*9*10^9)/17`
`F=-(27*10^9)/17`
`F=-1,59*10^9" "N`