Assuming human skin is at 98.6 degrees Fahrenheit, what wavelength is the peak in the human thermal radiation spectrum? What type of waves are these?
2 Answers
Explanation:
Wien's displacement law states that the black-body radiation curve for different temperatures peaks at a wavelength inversely proportional to the temperature.
where b is Wien's displacement constant, equal to
plugging this into our equation, we get the peak wavelength of radiated light:
This is in the range of what is called infrared radiation.
Should be the infrared fingerprint region.
We have a relationship for this called Wien's Displacement Law:
\mathbf(lambda_max = b/T) where:
b = 2.89777xx10^(-3) "m"cdot"K" is a proportionality constant, probably experimentally determined.T is temperature in"K" .lambda_max is the wavelength that you observe at its largest spectral energy density.
The spectral energy density is depicted in the following diagram, with respect to wavelength in
https://upload.wikimedia.org/
You can think of the spectral energy density as being proportional to the contribution of each wavelength range to some final observed color at a particular temperature. You can see that the peaks would correspond to
Converting temperature to
(98.6^@ "F" - 32) xx 5/9 = 37^@ "C"
37 + 273.15 ~~ color(green)("310.15 K")
And now we get a max wavelength of:
lambda_max = (2.89777xx10^(-3) "m"cdotcancel"K")/("310.15" cancel"K")
= 9.343xx10^(-6) "m"
Converting this to
= 9.343xx10^(-6) cancel("m") xx (10^6 mu"m")/(1 cancel"m")
= color(blue)(9.343) color(blue)(mu"m")
http://thesuiteworld.com/
Being close to