How do you solve the following system?: #y=2x-3 , 5x + 3y = -3 #

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Answer 1 · 2016-03-14T08:41:32

#x,y=6/11,-21/11#

#color(blue)(y=2x-3#

#color(blue)(5x+3y=-3#

Substitute the value of #y# to the second equation

#rarr5x+3(2x-3)=-3#

Use distributive property #color(brown)(a(b+c)=ab+ac#

#rarr5x+6x-9=-3#

#rarr11x-9=-3#

#rarr11x=-3+9#

#rarr11x=6#

#color(green)(rArrx=6/1

Substitute the value of #x# to the first equation

#rarry=2(6/11)-3#

#rarry=12/11-3#

#color(green)(rArry=-21/11#