Question

Question #959f8

Answer 1

`mass=2.18 g CaCl_2*6H_2O`

Explanation:

Take the molar mass of `CaCL_2*6H_2O`
`Ca = 1`x`40=40`
`Cl=2`x`35=70`
`H_2O=6`x`18=108`
Total=`218` grams per mole
2. All other data needed to solve the problem are given:
`V=100 ml=0.100 Li`
`M=0.1 (mol)/(Li)`
3. Plug in data using the formula:
`M=color(red)n/(Li solution)`
but:
`color(red)n=(mass)/(molar mass)`
4. Therefore; plug in the value to derive new formula to find the mass of `CaCl_2*6H_2O`
`M=((mass)/(molar mass))/(Li solution)`
5. Rearrange the formula isolating `mass`
`mass=molar mass`x`M`x`Li solution`
6. Plug in values and ensure to cancel out units to obtain `mass=2.18 g CaCl_2*6H_2O`