Question

How do you condense `1/3 log_3 x^6 + 1/6 log_3 x^6 - 1/9 log_3 x`?

Answer 1

`- 6 log_3 x`

Explanation:

Use log (a^m) = m log a and log (abc..) = log a + log b + log c +...

The expression is #log_3 (x^(6/3+6/6-9)) = log_3x^(-6) = -6 log_3 x#.