Question

Two charges of `-3 C` and `-4 C` are positioned on a line at points `-9` and `4`, respectively. What is the net force on a charge of `4 C` at `2`?

Answer 1

`F_1=F_2=0,64*10^9 " "N`

Explanation:

`"The force between two charges is given as:"`
`F_1=F_2=k(q_1*q_2)/d^2`
`d=9+4=13" "q_1=-3C" "q_2=-4C`
`F_1=F_2=9*19^9((-3)(-4))/13^2`
`F_1=F_2=(12*9*10^9)/169`