How do you find the derivative of #y = arctan(x^2)#?
1 Answer
Mar 16, 2016
Explanation:
Using the
#color(blue)" chain rule " #
#d/dx [ f(g(x)) ] = f'(g(x)) . g'(x) # and the standard derivative
#d/dx(tan^-1 x) = 1/(1 + x^2) #
#rArr dy/dx = 1/(1 + (x^2)^2) .d/dx (x^2) = (2x)/(1 + x^4) #
